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Convex sets - Convex Hull

Published by Angel on Wednesday, February 17, 2010 - 07:08:41 - Filed under Notes, Convex Sets

First post is on basic convex set theory, I liked this because it was simple, demonstration was not very hard either.

The convex hull for a set A ( Im using real A a subset of r.gif ) is the minimal convex set that contains A.
We’ll now define:

pconvex.gif

Lemma:

Let pointconvex.gif with A a convex set and pointinpk.gif then pina.gif

Proof:

We’ll use induction over k.
If k=1 then x*1 is in A ( we choose x that way ).
Now we’ll asume that it works for every k.
Now, let xconvex.gif where pinpk1.gif and xina.gif

We wanna see that x is in A.

Since pinpk1.gif then at least there is one pil1.gif, lets say its pk1l1.gif.

Let lambdaconvex.gif
and
yconvex.gif.

Then we know by our induction hypothesis that y is in A .
Now, since A is a convex set and yxk1ina.gif then xinaa.gif.

This shows that x is in A.

Definition:

A point xinrn.gif its a convex combination of points x1xninrn.gif if there is pointinpk.gif such that xeqp1pk.gif

Theorem:

Let ainrn.gif then c(A) ( The convex hull of the set A ) is the set of all convex combinations of all points in A.

Proof:

Let B the set of all convex combinations of points in A.
We now have to show that B=c(A) (convex hull of A )

1)

Let x be an element of B, then xeqp1pk.gif with x1xkina.gif and pointinpk.gif, since A is in c(A) then x1xkinca.gif , then p1x1pkxkinca.gif because c(A) is convex.
This shows that bsubca.gif.

2)

Note that if B is a convex set then A is a subset of B,this is because if x is in A then there is a pinp1.gif such that px will be on B. Then c(A) is a subset of B

We have to show that B is convex.

Let x and y be in B
Then xeqp1pk.gif and yeqq1qr.gif where x1yrina.gif and pointinpk.gif and pointinpr.gif.
Let oparamxy.gif with lambmugeq0.gif such that lambmueq1.gif
Then omegaeqpxqy.gif, it is clear now that lpmqeq1.gif
This shows that omegainb.gif, which means B is convex.

Then B=c(A).

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‘Till next time :)