Number theory - Möbius function
Published by Angel on
Friday, February 19, 2010 - 02:20:52
- Filed under Notes, Number theory
I like this function a lot, proposition is not THAT interesting but whatevs
———-
Lets define the Möbius function as:

Proposition:
is multiplicative and 
Proof:
Let gcd(m,n)=1
If
or 
Then 
If
,
, then

If n or m = 1 proof is clear.
Now, let
, since
is multiplicative then F(n) is multiplicative.
It is clear that 
Also:
.
( Möbius function is 0 on
)
Now, if we use prime factorization on n, if n>1:
we can do this because F(n) is multiplicative.
——–
I <3 Möbius function
Convex sets - Convex Hull
Published by Angel on
Wednesday, February 17, 2010 - 07:08:41
- Filed under Notes, Convex Sets
First post is on basic convex set theory, I liked this because it was simple, demonstration was not very hard either.
The convex hull for a set A ( Im using real A a subset of
) is the minimal convex set that contains A.
We’ll now define:

Lemma:
Let
with A a convex set and
then 
Proof:
We’ll use induction over k.
If k=1 then x*1 is in A ( we choose x that way ).
Now we’ll asume that it works for every k.
Now, let
where
and 
We wanna see that x is in A.
Since
then at least there is one
, lets say its
.
Let 
and
.
Then we know by our induction hypothesis that y is in A .
Now, since A is a convex set and
then
.
This shows that x is in A.
Definition:
A point
its a convex combination of points
if there is
such that 
Theorem:
Let
then c(A) ( The convex hull of the set A ) is the set of all convex combinations of all points in A.
Proof:
Let B the set of all convex combinations of points in A.
We now have to show that B=c(A) (convex hull of A )
1)
Let x be an element of B, then
with
and
, since A is in c(A) then
, then
because c(A) is convex.
This shows that
.
2)
Note that if B is a convex set then A is a subset of B,this is because if x is in A then there is a
such that px will be on B. Then c(A) is a subset of B
We have to show that B is convex.
Let x and y be in B
Then
and
where
and
and
.
Let
with
such that 
Then
, it is clear now that 
This shows that
, which means B is convex.
Then B=c(A).
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‘Till next time :)